The hydrolyiss of methyl acetate in aqueous solution is has been studied by titrating the liberated acetic acid against `NaOH`. The concentration of ester at different times is given below:
`|{:("t (min)",0,30,60,90),(C (Mol L^(-1)),0.8500,0.8004,0.7538,0.7096):}|`
Show that it follows a pseudo first order reaction, as the concentration of water remains nearly constant `(55 mol L^(-1))` during the course of the reaction . What is the value of `k'` in the equation ?
Rate `= k'[CH_(3)COOCH_(3)][H_(2)O]`

Explanation

To show that the hydrolysis of methyl acetate in aqueous solution follows a pseudo first-order reaction and to calculate the value of \( k' \), we will follow these steps:

### Step 1: Understand the Reaction
The hydrolysis of methyl acetate can be represented as:
\[ \text{CH}_3\text{COOCH}_3 + \text{H}_2\text{O} \rightarrow \text{CH}_3\text{COOH} + \text{CH}_3\text{OH} \]
In this reaction, methyl acetate reacts with water to produce acetic acid and methanol.
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