Pseudo first order rate for the reaction
`A + B rarr P`
when studied in `0.1 M` of `B` is given by
`-(d[A])/(dt) = -k[A]`
where `k = 1.85 xx 10^(4)s^(-1)`. Calculate the value of second order rate constant.

Explanation

To calculate the second-order rate constant for the reaction \( A + B \rightarrow P \) given that the pseudo first-order rate constant \( k \) is \( 1.85 \times 10^4 \, s^{-1} \) in a \( 0.1 \, M \) solution of \( B \), we can follow these steps:

### Step 1: Understand the Pseudo First-Order Condition
In a pseudo first-order reaction, one reactant (in this case, \( B \)) is in large excess, allowing us to treat its concentration as constant. The reaction can be simplified to a first-order reaction with respect to \( A \).

### Step 2: Write the Rate Expression
The rate of the reaction can be expressed as:
\[
...