For two firstorder reactions having same concentration of `A` and `B` at `t = 0`, use the given data to calculate the tempretature at which both occur with same rate.
Reaction I: `ArarrZ`, `k_(1) = 10^(16)e^((-(3000)/(T)))`
Reaction II: `BrarrY`, `k_(2) = 10^(15) e^((-(2000)/(T)))`

Explanation

To solve the problem, we need to find the temperature at which the rate constants \( k_1 \) and \( k_2 \) for two first-order reactions are equal.

### Step-by-Step Solution:

1. **Write the expressions for the rate constants:**
- For Reaction I:
\[
k_1 = 10^{16} e^{-\frac{3000}{T}}
...