The activation energy of the reaction: `A + B rarr` Products is `105.73 kJ mol^(-1)`. At `40^(@)C`, the Products are found at the rate of `0.133 mol L^(-1) min^(-1)`. What will be the rate of formation of Products at `80^(@)C`?

Explanation

To determine the rate of formation of products at 80°C, we can use the Arrhenius equation and the relationship between the rates at two different temperatures. Here’s a step-by-step solution:

### Step 1: Convert Temperatures to Kelvin
First, we need to convert the given temperatures from Celsius to Kelvin.

- **T1 = 40°C**
\( T1 = 40 + 273 = 313 \, K \)

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