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Conisder a reaction aG+bH rarr Products....

Conisder a reaction `aG+bH rarr` Products. When concentration of both the reactants `G` and `H` is doubled, the rate increases eight times. However, when the concentration of `G` is doubled, keeping the concentration of `H` fixed, the rate is doubled. The overall order of reaction is

A

`0`

B

`1`

C

`2`

D

`3`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the overall order of the reaction given the information about how the rate changes with varying concentrations of the reactants. ### Step-by-Step Solution: 1. **Write the Rate Law Expression**: The rate law for the reaction can be expressed as: \[ \text{Rate} = k [G]^x [H]^y \] where \(k\) is the rate constant, and \(x\) and \(y\) are the orders of the reaction with respect to reactants \(G\) and \(H\), respectively. 2. **Analyze the First Condition**: The first condition states that when the concentrations of both \(G\) and \(H\) are doubled, the rate increases eight times. This can be mathematically expressed as: \[ \text{Rate}' = k (2[G])^x (2[H])^y = 8 \times \text{Rate} \] Substituting the original rate expression, we have: \[ k (2[G])^x (2[H])^y = 8 \times k [G]^x [H]^y \] Simplifying this gives: \[ 2^x \cdot 2^y = 8 \] Since \(8 = 2^3\), we can equate the exponents: \[ x + y = 3 \quad \text{(Equation 1)} \] 3. **Analyze the Second Condition**: The second condition states that when the concentration of \(G\) is doubled while keeping \(H\) constant, the rate doubles: \[ \text{Rate}' = k (2[G])^x [H]^y = 2 \times \text{Rate} \] Again substituting the original rate expression, we have: \[ k (2[G])^x [H]^y = 2 \times k [G]^x [H]^y \] Simplifying gives: \[ 2^x = 2 \] This implies: \[ x = 1 \quad \text{(Equation 2)} \] 4. **Substitute \(x\) into Equation 1**: Now that we have \(x = 1\), we can substitute this value into Equation 1: \[ 1 + y = 3 \] Solving for \(y\) gives: \[ y = 2 \] 5. **Determine the Overall Order of Reaction**: The overall order of the reaction is the sum of the individual orders: \[ \text{Overall Order} = x + y = 1 + 2 = 3 \] ### Final Answer: The overall order of the reaction is **3**.

To solve the problem, we need to determine the overall order of the reaction given the information about how the rate changes with varying concentrations of the reactants. ### Step-by-Step Solution: 1. **Write the Rate Law Expression**: The rate law for the reaction can be expressed as: \[ \text{Rate} = k [G]^x [H]^y ...
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