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Which of the following graphs represents...

Which of the following graphs represents zero order if
`A rarr P` At `t = 0 rArr [A]_(0)` At `t = t rArr [A]_(t)`

A

B

C

D

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The correct Answer is:
To determine which graph represents a zero-order reaction for the reaction \( A \rightarrow P \), we need to analyze the characteristics of zero-order kinetics. ### Step-by-Step Solution: 1. **Understanding Zero-Order Reactions:** - In a zero-order reaction, the rate of reaction is constant and does not depend on the concentration of the reactant. The rate law can be expressed as: \[ \text{Rate} = k \] - Here, \( k \) is the rate constant. 2. **Mathematical Representation:** - For a zero-order reaction, the relationship between the concentration of reactant \( [A] \) and time \( t \) can be described by the equation: \[ [A]_0 - [A]_t = kt \] - Rearranging this gives: \[ [A]_t = [A]_0 - kt \] - This equation indicates that a plot of \( [A]_t \) versus time \( t \) will yield a straight line with a negative slope of \( -k \) and an intercept of \( [A]_0 \). 3. **Graphical Representation:** - The graph of \( [A]_t \) versus time \( t \) will be a straight line that starts at \( [A]_0 \) and decreases linearly over time. - The slope of the line will be negative, indicating that the concentration of \( A \) decreases as time increases. 4. **Identifying the Correct Graph:** - Among the given options, we need to look for a graph that shows a linear decrease in concentration over time, which corresponds to the equation derived above. 5. **Conclusion:** - The correct graph that represents a zero-order reaction will be a straight line with a negative slope, indicating a constant rate of reaction over time.

To determine which graph represents a zero-order reaction for the reaction \( A \rightarrow P \), we need to analyze the characteristics of zero-order kinetics. ### Step-by-Step Solution: 1. **Understanding Zero-Order Reactions:** - In a zero-order reaction, the rate of reaction is constant and does not depend on the concentration of the reactant. The rate law can be expressed as: \[ \text{Rate} = k ...
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