The data for the reaction: `A + B overset(k)rarr C`.
`|{:("Experiment",[A]_(0),[B]_(0),"Initial rate"),(1,0.012,0.035,0.10),(2,0.024,0.070,0.80),(3,0.024,0.035,0.10),(4,0.012,0.070,0.80):}|`
The rate law corresponding to the above data is
(a) Rate `= k[B]^(3)` , (b) Rate `= k[B]^(4)`
( c) Rate `= k[A][B]^(3)` , (d) Rate `= k[A]^(2)[B]^(2)`

Options

A. Rate `= k[B]^(3)`
B. Rate `= k[B]^(4)`
C. Rate `= k[A][B]^(3)`
D. Rate `= k[A]^(2)[B]^(2)`

Answer

A

Explanation

form experiments `(3)` and `(2)`, `[A]` is constant and `[B]` is doubled and rates becomes `8` times, so order w.r.t. `[B] = 3`.
form experiments `(1)` and `(3)`, `[B]` is constant and `[A]` is doubled, but rate does not change, so order w.r.t `[A] = 0`. Thus,
rate `= k[B]^(3)`