The reaction `A(g) + 2B(g) rarr C(g) + D(g)` is an elementary process. In an experiment involvig this reaction, the initial partial pressure of `A` and `B` are `p_(A) = 0.60 atm` and `p_(B) = 0.80 atm`, respectively. When `p_(C ) = 0.20 atm`, the rate of reaction relative to the initial rate is

Options

A. `1//48`
B. `1//24`
C. `9//16`
D. `1//6`

Answer

D

Explanation

`r_(1) = k[A][B]^(2) = k[0.6][0.80]^(2)`
After reaction
`{:(A+,2B,rarr,C+,D),(0.6-0.2,0.8-0.4,,0.2,0.2),(0.4,0.4,,0.2,0.2):}`
`(r_(1))/(r_(1)) = (k(0.4)(0.4)^(2))/((0.6)(0.8)^(2)) = (1)/(6)`