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In the Wilhelmey equation of a first ord...

In the Wilhelmey equation of a first order reaction `c_(t) = c_(0)e^(-kt)`. If the initial concentration `c_(0)` is increased `m` times, then

A

The value of `k` will increase `m` times

B

The value of `k` will decrease `m` times

C

The value of `k` will remain unchanged

D

None of these

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The correct Answer is:
To solve the problem, we need to analyze the effect of increasing the initial concentration \( c_0 \) on the rate constant \( k \) in the context of a first-order reaction described by the equation: \[ c_t = c_0 e^{-kt} \] ### Step-by-Step Solution: 1. **Understand the First-Order Reaction**: The given equation \( c_t = c_0 e^{-kt} \) describes the concentration of a reactant at time \( t \) for a first-order reaction. Here, \( c_0 \) is the initial concentration, \( c_t \) is the concentration at time \( t \), and \( k \) is the rate constant. **Hint**: Recall that in a first-order reaction, the rate of reaction depends linearly on the concentration of one reactant. 2. **Effect of Increasing Initial Concentration**: The problem states that the initial concentration \( c_0 \) is increased \( m \) times, which means the new initial concentration becomes \( mc_0 \). **Hint**: Consider how the rate of reaction is defined for first-order kinetics. 3. **Rate of Reaction**: For a first-order reaction, the rate \( r \) is given by: \[ r = k [A] \] where \( [A] \) is the concentration of the reactant. If we increase \( c_0 \) to \( mc_0 \), the rate becomes: \[ r' = k (mc_0) \] However, the rate constant \( k \) itself is a characteristic of the reaction and does not change with concentration. **Hint**: Remember that the rate constant \( k \) is independent of the concentration for first-order reactions. 4. **Conclusion**: Since the rate constant \( k \) is independent of the initial concentration in a first-order reaction, increasing \( c_0 \) to \( mc_0 \) does not affect the value of \( k \). Therefore, the value of \( k \) remains constant. **Final Answer**: The value of \( k \) will remain unchanged. ### Summary of the Answer: When the initial concentration \( c_0 \) is increased \( m \) times in a first-order reaction, the rate constant \( k \) remains constant.

To solve the problem, we need to analyze the effect of increasing the initial concentration \( c_0 \) on the rate constant \( k \) in the context of a first-order reaction described by the equation: \[ c_t = c_0 e^{-kt} \] ### Step-by-Step Solution: ...
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