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For a reaction, the rate constant is exp...

For a reaction, the rate constant is expressed as `k = Ae^(-40000//T)`. The energy of the activation is

A

`40000 cal`

B

`88000 cal`

C

`80000 cal`

D

`8000 cal`

Text Solution

Verified by Experts

The correct Answer is:
C
`k = Ae^(-E_(a)//RT)`
`:. (-E_(a))/(R ) = -40000`
`:. E_(a) = 40000 xx 2 = 80000 cal`
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