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If a reaction involves gaseous reactants...

If a reaction involves gaseous reactants and Products, the units of its rate are

A

atm

B

atm-`s`

C

atm-`s^(-1)`

D

`atm^(2) s^(2)`

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The correct Answer is:
To determine the units of the rate of a reaction involving gaseous reactants and products, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Definition of Rate**: The rate of a reaction is defined as the change in concentration of a reactant or product over time. Mathematically, this can be expressed as: \[ \text{Rate} = -\frac{d[A]}{dt} \] where \([A]\) is the concentration of the reactant A, and \(t\) is time. 2. **Identify the Units of Concentration**: The concentration of a substance is typically expressed in moles per liter (mol/L), which can also be written as: \[ \text{Concentration} = \text{mol} \cdot \text{L}^{-1} \] 3. **Incorporate Time into the Rate Expression**: Since the rate is the change in concentration over time, we need to include the unit of time. If we consider time in seconds, the unit for the rate becomes: \[ \text{Rate} = -\frac{d[A]}{dt} \Rightarrow \text{Units of Rate} = \frac{\text{mol} \cdot \text{L}^{-1}}{\text{s}} = \text{mol} \cdot \text{L}^{-1} \cdot \text{s}^{-1} \] 4. **Relate Concentration to Pressure**: For gaseous reactants and products, we can relate concentration to pressure using the ideal gas law: \[ PV = nRT \Rightarrow P = \frac{n}{V}RT \] Here, \(P\) (pressure) can be expressed in terms of concentration since \(C = \frac{n}{V}\). Thus, at constant temperature, pressure is directly proportional to concentration. 5. **Express Rate in Terms of Pressure**: Therefore, we can express the rate in terms of pressure: \[ \text{Rate} = -\frac{dP}{dt} \] 6. **Determine the Units of Pressure**: If we consider the unit of pressure as atmospheres (atm), then the unit of the rate becomes: \[ \text{Units of Rate} = \frac{\text{atm}}{\text{s}} = \text{atm} \cdot \text{s}^{-1} \] ### Final Answer: The units of the rate for a reaction involving gaseous reactants and products are: \[ \text{atm} \cdot \text{s}^{-1} \]
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