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For a chemical reaction A rarr Products,...

For a chemical reaction `A rarr` Products, the rate of reaction doubles when the concentration of `A` is increased by `4` times. The order of reaction is

A

`2`

B

`1`

C

`1//2`

D

Zero

Text Solution

Verified by Experts

The correct Answer is:
C
`r_(1) = k[A]^(n)`
`r_(2) = 2r_(1) = k[4A]^(n)`
`(2r_(1))/(r_(1)) = (4)^(n)`
`(2)^(1) = (2)^(2n)`
`n = (1)/(2)`
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