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Assertion (A) : The rate constant of a z...

Assertion (A) : The rate constant of a zero order reaction has same units as the rate of reaction.
Reason (R ): Rate constant of a zero order reaction does not depend upon the units of concentration.

A

If both `(A)` and `(R )` are correct, and `(R )` is the correct explnation of `(A)`.

B

If both `(A)` and `(R )` are correct, but `(R )` is noth the correct explanation of `(A)`.

C

If `(A)` is correct, but `(R )` is incorrect.

D

If `(A)` is incorrect, but `(R )` is correct.

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The correct Answer is:
To solve the given question, we need to analyze both the assertion (A) and the reason (R) provided. ### Step-by-Step Solution: 1. **Understanding Zero Order Reactions**: - In a zero-order reaction, the rate of reaction is independent of the concentration of the reactants. This means that the rate remains constant regardless of how much reactant is present. 2. **Rate Equation for Zero Order Reactions**: - The rate of a zero-order reaction can be expressed as: \[ \text{Rate} = k[A]^0 = k \] - Here, \( k \) is the rate constant and \([A]\) is the concentration of the reactant. Since any number raised to the power of zero is 1, the equation simplifies to the rate being equal to \( k \). 3. **Units of the Rate Constant (k)**: - The units of the rate constant \( k \) for a zero-order reaction can be derived from the general formula for the rate constant: \[ \text{Units of } k = \text{(mole/L)}^{1-n} \cdot \text{s}^{-1} \] - For a zero-order reaction, \( n = 0 \): \[ \text{Units of } k = \text{(mole/L)}^{1-0} \cdot \text{s}^{-1} = \text{mole/L} \cdot \text{s}^{-1} \] 4. **Units of Rate of Reaction**: - The rate of reaction is also expressed in terms of concentration change over time, which has the same units as \( k \): \[ \text{Rate} = \frac{\Delta [A]}{\Delta t} \quad \text{(change in concentration over time)} \] - Thus, the units of rate of reaction are also \(\text{mole/L} \cdot \text{s}^{-1}\). 5. **Conclusion on Assertion (A)**: - Since both the rate constant \( k \) and the rate of reaction have the same units of \(\text{mole/L} \cdot \text{s}^{-1}\), the assertion (A) is correct. 6. **Analyzing Reason (R)**: - The reason states that the rate constant of a zero-order reaction does not depend upon the units of concentration. This is true because the rate of a zero-order reaction is constant and does not change with varying concentrations of reactants. - Therefore, the reason (R) is also correct. 7. **Final Evaluation**: - Both assertion (A) and reason (R) are correct, and R provides the correct explanation for A. Hence, the correct answer is that both A and R are correct, and R is the correct explanation of A. ### Final Answer: Both A and R are correct, and R is the correct explanation of A. ---

To solve the given question, we need to analyze both the assertion (A) and the reason (R) provided. ### Step-by-Step Solution: 1. **Understanding Zero Order Reactions**: - In a zero-order reaction, the rate of reaction is independent of the concentration of the reactants. This means that the rate remains constant regardless of how much reactant is present. 2. **Rate Equation for Zero Order Reactions**: ...
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