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In an experiment, 200 mL of 0.5M oxalic ...

In an experiment, `200 mL` of `0.5M` oxalic acid is shaken with `10 g` of activated charcoal and filtered. The concentration of the filtrate is reduced to `0.4 M`. The amount of adsorption `(x//m)` is
(a) `0.9` b. `1.8` c. `0.18` d. `0.09`

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To solve the problem step by step, we need to determine the amount of adsorption (x/m) of oxalic acid onto activated charcoal. Here’s how we can do that: ### Step 1: Determine the initial and final concentrations of oxalic acid - Initial concentration of oxalic acid (C1) = 0.5 M - Final concentration of oxalic acid (C2) = 0.4 M ### Step 2: Calculate the change in concentration - Change in concentration (ΔC) = C1 - C2 = 0.5 M - 0.4 M = 0.1 M ...
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