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At 400K , the energy of activation of a ...

At `400K` , the energy of activation of a reaction is decreased by `0.8Kcal` in the presence of catalyst. Hence, the rate will be
a. Increased by `2.73` times
b. Increased by `1.18` times
c. Decreased by `2.72` times
d. Increased by `6.26` times

Text Solution

AI Generated Solution

To solve the problem, we will use the Arrhenius equation, which relates the rate constant of a reaction to its activation energy and temperature. The steps are as follows: ### Step-by-Step Solution: 1. **Understand the given data**: - Activation energy decrease (ΔE) = -0.8 kcal = -0.8 × 10³ cal - Temperature (T) = 400 K ...
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