In a coagulation experiment, `5mL` of `As_(2)S_(3)` is mixed with distilled water and `0.1M` solution of an electrolyte `AB` so that the total volume is `10mL` . It was found that all solutions sontianing more than `4.6mL` . Of `AB` coagulate within `5` min. What is the flocculation value of `AB` for `As_(2)S_(3)` solution?

Explanation

To solve the problem, we need to find the flocculation value of the electrolyte \( AB \) for the colloidal solution of \( As_2S_3 \). The flocculation value is defined as the minimum amount of electrolyte (in millimoles) required to completely coagulate 1 liter of a colloidal solution.

### Step-by-Step Solution:

1. **Identify the given information:**
- Volume of \( As_2S_3 \) solution = 5 mL
- Total volume after mixing with distilled water and \( AB \) = 10 mL
- Volume of \( AB \) that causes coagulation = 4.6 mL
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