Combination of `N_(2)` and `H_(2)` in the presence of `Fe` as a catalyst is an example of heterogeneous catalysis.

Answer

To determine whether the statement "Combination of N₂ and H₂ in the presence of Fe as a catalyst is an example of heterogeneous catalysis" is true or false, we can analyze the components involved in this reaction.

### Step-by-Step Solution:

1. **Identify the Reactants and Catalyst**:
- The reactants in the reaction are nitrogen (N₂) and hydrogen (H₂).
- The catalyst used in this reaction is iron (Fe).

2. **Determine the Physical States**:
- Nitrogen (N₂) is a gas.
- Hydrogen (H₂) is also a gas.
- Iron (Fe), as a catalyst, is in solid state.

3. **Understand Heterogeneous Catalysis**:
- Heterogeneous catalysis occurs when the catalyst is in a different phase than the reactants. This means that if the reactants are gases and the catalyst is a solid, it is classified as heterogeneous catalysis.

4. **Analyze the Given Reaction**:
- In the Haber process, nitrogen gas (N₂) reacts with hydrogen gas (H₂) in the presence of solid iron (Fe) to produce ammonia (NH₃).
- The reaction can be summarized as:
\[ N_2(g) + 3H_2(g) \xrightarrow{Fe} 2NH_3(g) \]
- Here, both nitrogen and hydrogen are in the gaseous state, while iron is in the solid state.

5. **Conclusion**:
- Since the catalyst (Fe) is in a different phase (solid) compared to the reactants (N₂ and H₂, which are both gases), this reaction is indeed an example of heterogeneous catalysis.
- Therefore, the statement is **true**.

### Final Answer:
The statement is **true**.

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