Radium is a radioactive substance. It dissolves in dilute `H_(2)SO_(4)` and forms a compound radium sulphate. The compound is

Options

A. No longer radioactive
B. Half as radioactive as the radium content
C. As radioactive as the radium content
D. Twice as radioactive as the radium content.

Explanation

To solve the question regarding the compound formed when radium dissolves in dilute `H₂SO₄`, we need to analyze the situation step by step.

### Step 1: Identify the Compound
When radium (Ra) reacts with dilute sulfuric acid (H₂SO₄), it forms radium sulfate. The chemical formula for radium sulfate is RaSO₄.

### Step 2: Understand the Nature of Radium
Radium is a radioactive element. Its radioactivity is a property that originates from its atomic nucleus, specifically from the presence of protons and neutrons (collectively known as nucleons).

### Step 3: Consider the Effect of Compound Formation
When radium reacts with sulfuric acid to form radium sulfate, the process involves the formation of ionic bonds where radium donates electrons to form the radium ion (Ra²⁺) and the sulfate ion (SO₄²⁻). However, the formation of this compound does not change the number of protons or neutrons in the radium nucleus.

### Step 4: Analyze the Radioactivity
Since the radioactivity of an element is determined by the number of nucleons in its nucleus, and since these nucleons do not change when radium forms a compound, the radioactivity of radium remains the same after the formation of radium sulfate.

### Conclusion
Thus, the correct statement about the compound radium sulfate is that its radioactivity will remain the same as that of the radium before the reaction.

### Final Answer
The compound radium sulfate (RaSO₄) retains the same level of radioactivity as radium itself.

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