An atom of radium combines with two atoms of chlorine of form `RaCl_(2)` molecule. The radioactivity of `RaCl_(2)` will be

Options

A. Zero
B. `1//3` of the same quantity of radium
C. As much as that of same quantity of radium
D. `1//4` of the same quantity of radium

Answer

To determine the radioactivity of the compound radium chloride (RaCl₂), we need to analyze the properties of the elements involved and how they interact in the formation of the compound.

### Step-by-Step Solution:

1. **Identify the Elements and Their Properties**:
- Radium (Ra) is a radioactive element. It has a nucleus that undergoes radioactive decay, emitting radiation.
- Chlorine (Cl) is a non-radioactive element. It does not have a radioactive nucleus and does not contribute to radioactivity.

2. **Formation of Radium Chloride**:
- When radium combines with two chlorine atoms, it forms the compound RaCl₂. In this compound, radium is the only element that possesses radioactivity.

3. **Understanding the Role of Valence Electrons**:
- The formation of chemical bonds (like the ionic bond in RaCl₂) involves the outermost electrons (valence electrons) of the atoms. The nucleus of the radium atom, which is responsible for its radioactivity, does not participate in the bond formation.

4. **Radioactivity and Nucleus**:
- Radioactivity is a property that arises from the instability of the nucleus of an atom. Since the nucleus of radium remains unchanged when it forms a bond with chlorine, the radioactivity of radium is not affected by the formation of RaCl₂.

5. **Conclusion**:
- The radioactivity of the compound RaCl₂ will be the same as the radioactivity of the radium atom alone. Therefore, the radioactivity of RaCl₂ is equivalent to that of the same quantity of radium.

### Final Answer:
The radioactivity of `RaCl_(2)` will be the same as that of the same quantity of radium.

---