`._(7)N^(14)+ ._(0)n^(1)rarr ...................+._(1)H^(1)`

Answer

To solve the nuclear reaction involving nitrogen and neutron bombardment, we can break it down into clear steps:

### Step 1: Write the initial reaction
The reaction begins with a nitrogen-14 nucleus and a neutron:
\[ _{7}^{14}N + _{0}^{1}n \rightarrow ? \]

### Step 2: Identify the products
When nitrogen-14 is bombarded with a neutron, it can produce carbon-14 and a proton. The reaction can be represented as:
\[ _{7}^{14}N + _{0}^{1}n \rightarrow _{6}^{14}C + _{1}^{1}H \]

### Step 3: Balance the reaction
Now we need to ensure that both sides of the equation are balanced in terms of atomic numbers and mass numbers.

- **Left Side:**
- Atomic number: \(7 + 0 = 7\)
- Mass number: \(14 + 1 = 15\)

- **Right Side:**
- Atomic number: \(6 + 1 = 7\)
- Mass number: \(14 + 1 = 15\)

Both sides are balanced:
- Atomic numbers: 7 on both sides
- Mass numbers: 15 on both sides

### Final Balanced Reaction
Thus, the balanced nuclear reaction is:
\[ _{7}^{14}N + _{0}^{1}n \rightarrow _{6}^{14}C + _{1}^{1}H \]

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