Home
Class 12
CHEMISTRY
Calculate the number of neutrons emitted...

Calculate the number of neutrons emitted when `._(92)U^(235)` undergoes controlled nuclear fission to `._(54)Xe^(142) ` and `._(38)Sr^(90)`.

Text Solution

AI Generated Solution

To solve the problem of calculating the number of neutrons emitted when Uranium-235 undergoes controlled nuclear fission to produce Xenon-142 and Strontium-90, we will follow these steps: ### Step 1: Write the nuclear fission equation The fission reaction can be represented as follows: \[ _{92}^{235}\text{U} \rightarrow _{54}^{142}\text{Xe} + _{38}^{90}\text{Sr} + x \, _{0}^{1}\text{n} \] ...
Promotional Banner

Topper's Solved these Questions

  • NUCLEAR CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise True//False Type|1 Videos

  • NCERT BASED EXERCISE

    CENGAGE CHEMISTRY ENGLISH|Exercise Nuclear Chemistry (NCERT Exercise)|29 Videos

  • ORGANIC COMPOUNDS WITH FUNCTIONAL GROUP

    CENGAGE CHEMISTRY ENGLISH|Exercise Archives Analytical And Descriptive|24 Videos

Similar Questions

Explore conceptually related problems

The number of neutrons released when ._92 U^235 undergoes fission by absorbing ._0 n^1 and (._56 Ba^144 + ._36 Kr^89) are formed, is.

Calculate the number of neutrons in the remaining atoms after the emission of an alpha particle from ._(92)U^(238) atom.

The ._(92)U^(235) absorbs a slow neturon (thermal neutron) & undergoes a fission represented by ._(92)U^(235)+._(0)n^(1)rarr._(92)U^(236)rarr._(56)Ba^(141)+_(36)Kr^(92)+3_(0)n^(1)+E . Calculate: The energy released when 1 g of ._(92)U^(235) undergoes complete fission in N if m=[N] then find (m-2)/(5) . [N] greatest integer Given ._(92)U^(235)=235.1175"amu (atom)" , ._(56)Ba^(141)=140.9577 "amu (atom)" , ._(36)r^(92)=91.9263 "amu(atom)" , ._(0)n^(1)=1.00898 "amu", 1 "amu"=931 MeV//C^(2)

U-235 is decayed by bombardment by neutron as according to the equation: ._(92)U^(235) + ._(0)n^(1) rarr ._(42)Mo^(98) + ._(54)Xe^(136) + x ._(-1)e^(0) + y ._(0)n^(1) Calculate the value of x and y and the energy released per uranium atom fragmented (neglect the mass of electron). Given masses (amu) U-235 = 235.044 , Xe = 135.907, Mo = 97.90, e = 5.5 xx 10^(-4), n = 1.0086 .

The average number of neutrons released per fission in the fission of U^235 is

Name the reaction which takes place when a slow neutron beam strikes ._(92)^(235)U nuclei. Write the nuclear reaction involved.

Calculate the ground state Q value of the induced fission raction in the equation n+._(92)^(235) Urarr._(92)^(236)Uastrarr._(40)^(99)Zr+._(52)^(134)Te+2n If the neutron is thermal. A thermal neutorn is in thermal equilibrium with its envitronmnet, it has an avergae kinetic energy given by (3//2) kT . Given : m(n) =1.0087 am u, M(.^(235)U)=235.0439) am u , M(.^(99)Zr)=98.916 am u, M(.^(134)Te)=133.9115 am u .

The number of neutrons accompanying the formation of ._(54)Xe^(139) and ._(38)Sr^(94) from the absorption of a slow neutron by ._(92)U^(235) , followed by nuclear fission is

Complete the following nuclear equation by suppling the symbol for the other product of the fission : ._(92)^(235)U+_(0)^(1)n rarr _(38)^(94)Sr +………+2_(0)^(1)n

Calculate the energy released by fission from 2 gm of ._92U^235 in KWH. Given that the energy released per fission is 200 Mev.