Henry's law constant for molality of methane in benzene at 298 K is `4.27xx10^5` mm Hg. The mole fraction of methane in benzene at 298 K under 760 mm Hg is

Answer

`1.78xx10^(-3)`

Explanation

Given `K_(H)=4.27xx10^(5)mm`
`p=760mm`
Using Henry's law `:`
`p=K_(H)CHMi,CHMi=(p)/(K_(H))=(760)/(4.27XX10^(5))mm`