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Calculate the mf of the cell in which th...

Calculate the mf of the cell in which the following reaction takes place
`Ni(s)+2Ag^(+)(0.002M)toNi^(2+)(0.160M)+2Ag(s)`
given that `E_(cell)^(Ө)=1.05V`

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Verified by Experts

The correct Answer is:
`0.91V`
`E_(cell)=E_(cell)^(c-)-(0.0591)/(n)log``([Ni^(2+)])/([Ag^(o+)])`
`=1.05-(0.0591)/(2)log``(0.0160)/((0.002)^(2))`
`=1.05-(0.0591)/(2)log(4xx10^(4))`
`=1.05-(0.0591)/(2)log(4.6021)`
`=1.05-0.14V=0.91V`
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