Consider the reaction: `Cr_(2)O_(7)^(2-)+14H^(+)+6e^(-)to2Cr^(3+)+7H_(2)O`
what is the quantity of electricity in coulombs needed to reduce 1 mol
of `Cr_(2)O_(7)^(2-)`?

Answer

`579000C`

Explanation

Form the given reactions, `1 mol of Cr_(2)O_(7)^(2-)` ions require `6F=6xx96500C=57900C` of electricity for reduction to `Cr^(3+)`.