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The resistace of a conductivity cell con...

The resistace of a conductivity cell containing 0.001 M KCl solution at 298K is `1500Omega` what is the cell constant if conductivity of 0.001M KCl solution at 298 K is `0.146xx10^(-3)S" "cm^(-1)`

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The correct Answer is:
`0.219cm^(-1)`
Cell constant `(G^(**))=(Conductivity(k))/(Conduct ance(G))=kxxR`
`=0.146xx10^(-3)Scm^(-1)xx1500ohm`
`=0.219cm^(-1)`
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