The rate constant for a first order reaction is `60 s^(–1)`. How much time will it take to reduce the initial concentration of the reactant to its `1/16^(th)` value?

Answer

`4.6xx10^(-2)s`

Explanation

`k=(2.303)/(t)log``(a)/(a-x)`
`a=1M, a-x=(1)/(16)M,k=60s^(-1)`
`t=(2.303)/(60)log``(1)/(1)=0.03838xxlog16`
`=0.03838xx1.2041`
`=4.6xx10^(-2)s`