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The decomposition of a hydrocarbon follo...

The decomposition of a hydrocarbon follows the equation `k = (4.5 xx 10^(11) s^(-1)) e^(-28000 K//T)`. What will be the value of activation energy ?

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The correct Answer is:
`232.79kJ mol^(-10`
According to Arrhenius equation `k=Ae^(-Ea//RT)`
`:. (-E_(a))/(RT)=-(28000K)/(T)`
or `E_(a)=28000KxxR`
`=28000Kxx8.314K ^(-1) mol^(-1)=232.79 kJ mol^(-1)`
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