Given the `IUPAC` names of the following compounds:
(i) `CH_(3)CH_(2)CH_(2)underset(C_(2)H_(5))underset(|)overset(CH_(3))underset(|)(C )CH_(2)-overset(CH_(3))overset(|)(C )=CH_(2)`
(ii) `CH_(3)-overset(CH_(3))overset(C )H-C-=CH`
(iii) `C_(6)H_(5)-CH=CH-CH_(2)Cl`
`CH_(3)CH-CH-CH_(2)Cl`
(iv) `CH_(3)CH=CH-CH_(2)Br`
v `CH_(2)=CH-overset(Cl)overset(|)(C )-CH=CH_(2)`
vi `CH_(2)=CH-overset(CH_(2)CH_(3))underset(|)(C )H-underset(Cl)underset(|)(C )=CH_(2)`
vii. `(CH_(3))_(3)C - CH=CH_(2)`

Explanation

To derive the IUPAC names for the given compounds, we will follow a systematic approach. Here’s a step-by-step solution for each compound:

### Compound (i):
**Structure**: `CH₃CH₂CH₂C(C₂H₅)(CH₃)C(CH₃)=CH₂`

1. **Identify the Longest Carbon Chain**: The longest chain has 7 carbons (heptane).
2. **Number the Chain**: Start numbering from the end nearest to the double bond. The double bond is at position 1.
3. **Identify Substituents**: There are two methyl groups (at positions 2 and 4) and one ethyl group (at position 3).
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