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a. Compare the size of Cl, and Cl^(ɵ) io...

a. Compare the size of `Cl, and Cl^(ɵ)` ion.
b. the radii of `Ar` is greater than the radii of chlorine. Explain.

Text Solution

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a. `(Z)/(e^(-))` ratio for `Cl = (17)/(17) = 1.00`
`Cl^(ɵ) = (17)/(18) = 0.944`
`Fe^(2+) = (26)/(24) = 1.08`
`Cl^(ɵ) gt Cl gt Fe^(2+)`
b. Explanation: In chlorine, the radii mean the atomic or covalent radii which is actually half the intermolecular distance between two atoms, whereas in argon the radii mean the van der Waals radii as argon is not a diatomic molecule. van der Waals radii is actually half the distance between adjacent molecule. So, van der Waals radii being larger than the atomic radii. Hence, argon has a larger radii than chlorine.
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