Home
Class 11
CHEMISTRY
The sum of IE(1) and IE(2) and those of ...

The sum of `IE_(1)` and `IE_(2)` and those of `IE_(2)` and those of `IE_(3)` and `IE_(4)` in `(kJ mol^(-1))` of `Ni` and `Pt` are :
`{:(,(IE_(1)+IE_(2)),(IE_(2)+IE_(4)),"Total",),(Ni,2.5 xx 10^(3),8.8 xx 10^(3),11.3 xx 10^(3),),(Pt,2.7 xx 10^(3),6.7 xx 10^(3),9.4 xx 10^(3),):}`
a. What is the most common oxidation state (O.S.) of `Ni` and `Pt`.

Text Solution

AI Generated Solution

To determine the most common oxidation states of Nickel (Ni) and Platinum (Pt) based on the given ionization energies, we will analyze the provided data step by step. ### Step 1: Analyze the Ionization Energies of Nickel (Ni) The given values for Nickel (Ni) are: - \(IE_1 + IE_2 = 2.5 \times 10^3 \, kJ/mol\) - \(IE_2 + IE_4 = 8.8 \times 10^3 \, kJ/mol\) ...
Promotional Banner

Topper's Solved these Questions

  • PERIODIC CLASSIFICATION OF ELEMENTS AND GENERAL INORGANIC CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Solved Examples|34 Videos

  • PERIODIC CLASSIFICATION OF ELEMENTS AND GENERAL INORGANIC CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Ex 1.1|14 Videos

  • P-BLOCK GROUP 14 - CARBON FAMILY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Archives (Subjective)|9 Videos

  • PURIFICATION OF ORGANIC COMPOUNDS AND QUALITATIVE AND QUANTITATIVE ANALYSIS

    CENGAGE CHEMISTRY ENGLISH|Exercise Assertion Reasoning Type|5 Videos

Similar Questions

Explore conceptually related problems

Find the number : a. (4xx10^(5))+(3xx10^(2))+(7xx10^(0)) b. (3xx10^(6))+(8xx10^(3))+(1xx10^(1))

Simplify : (4xx10^(-2))-(2.5xx10^(-3))

The sum of IE_(1) and IE_(2), IE_(3) and IE_(4) for element P and Q are given below: {:(,IE_(1)+IE_(2),IE_(2)+IE_(4)),((P),2.45,8.82),((Q),2.85,6.11):} Then according to the given information the correct statement (s) is/are

For a reaction 2NO(g) + 2H_(2)(g) rarr N_(2)(g)+2H_(2)O(g) the following data were obtained: |{:(,[NO] (mol L^(-1)),[H_(2)] (mol L^(-1)),"Rate" (mol L^(-1) s^(-1))),(1.,5 xx 10^(-3),2.5 xx 10^(-3),3 xx 10^(-5)),(2.,15 xx 10^(-3),2.5 xx 10^(-3),9xx10^(-5)),(3.,15 xx 10^(-3),10 xx 10^(-3),3.6 xx 10^(-4)):}| (a) Calculating the order of reactions. (b) Find the rate constant. (c ) Find the initial rate if [NO] = [H_(2)] = 8.0 xx 10^(-3) M

Ionisation energies of Ni and Pt in Kjmol^(-1) are given below {:(,ubrace((IE)_(1)+(IE)_(2)),ubrace((IE)_(3)+(IE)_(4))),(Ni,2.49,8.80),(Pt,2.60,6.70):} So, (select the correct statement)

Simplify. (i) (25 xx t^(-4))/(5^3 xx 10 xx t^(-8)) (t != 0) (ii) (3^(-5) xx 10^(-5) xx 125)/(5^(-7) xx 6^(-5))

Simplify: (i) ((2^5)2 xx 7^3)/(8^3 xx 7) (ii) (25 xx 5^2 xx t^8)/(10^3 xx t^4)

{:("Column A"," ","Column B"),(2 xx 10^1 + 3 xx 10^(0) +4 xx 10^(-1) + 5 xx 10^(-2),,1 xx 10^(-3) + 2 xx 10^(-2) xx 10^(-2) + 3 xx 10^(-1) + 4 xx 10^(0) + 5 xx 10^(1)):}

For the reaction A + B to products, what will be the order of reaction with respect to A and B? {:("Exp",[A](mol L^(-1)),[B](mol L^(-1)),"Initial rate (mol L^(-1) s^(-1))),(1,2.5 xx 10^(-4), 3 xx 10^(-5), 5 xx 10^(-4)),(2,5 xx 10^(-4),6 xx 10^(-5), 4 xx 10^(-3)),(3, 1xx 10^(-3), 6 xx 10^(-5), 1.6 xx 10^(-2)):}

Express the following numbers in usual form. (i) 3.02 xx 10^-6 (ii) 4.5 xx 10^4 (iii) 3 xx 10^(-8) (iv) 1.0001 xx 10^9 (v) 5.8 xx 10^12 (vi) 3.61492 xx 10^6