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The amount of energy released when 10^(1...

The amount of energy released when `10^(12)` atoms of `Cl` vapours are converted to `Cl^(ɵ)` ions, according to the equation :
`Cl_((g))+e^(-) rarr Cl_((g))^(ɵ)` is `58 xx 10^(-10)J`
Calculate the `Delta_(eg)H^(ɵ)` of `Cl` atom in `kJ mol^(-1)` and `eV "atom"^(-1)`.

Text Solution

AI Generated Solution

To calculate the ΔegH° of Cl atom in kJ mol⁻¹ and eV atom⁻¹, we will follow these steps: ### Step 1: Understand the given data We are given that the energy released when \(10^{12}\) atoms of Cl are converted to Cl⁻ ions is \(58 \times 10^{-10}\) J. This corresponds to the reaction: \[ \text{Cl}_{(g)} + e^- \rightarrow \text{Cl}_{(g)}^{\circ} \] ### Step 2: Calculate the energy released per atom To find the energy released per atom, we divide the total energy by the number of atoms: ...
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