How many `Cl` atoms can you ionise in the process ` Cl rarr Cl^+ + e,` by the energy liberated for the process ` Cl + e rarr rarr Cl^-` for one Avogadro's number of atoms ? (Given : `IP = 13. 0 eV ` and `EA = 3.60 eV`) .

Explanation

To determine how many chlorine (Cl) atoms can be ionized using the energy liberated from the formation of Cl^- ions, we can follow these steps:

### Step 1: Understand the energy requirements and releases
- The ionization process of Cl to Cl^+ requires energy equal to the ionization potential (IP), which is given as 13.0 eV.
- The formation of Cl^- from Cl and an electron releases energy equal to the electron affinity (EA), which is given as 3.60 eV.

### Step 2: Calculate the total energy released for one Avogadro's number of Cl^- formation
- One Avogadro's number of atoms is \(6.022 \times 10^{23}\).
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