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The conservation of gaseous atoms K and ...

The conservation of gaseous atoms `K` and `F` to `K^(o+)` and `F^(ɵ)` absorbs `0.85 eV` of energy. If the `IE` and `Delta_("eg")H^(ɵ)` of `K` and `F` have magnitudes in the ratio of `7:6`, what is the electron gain enthalpy `(Delta_("eg")H^(ɵ))` of fluorine ?

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To solve the problem, we will follow these steps: ### Step 1: Define the variables Let: - \( x \) = Ionization energy (IE) of potassium (K) - \( y \) = Electron gain enthalpy (\( \Delta_{eg}H^\circ \)) of fluorine (F) ### Step 2: Write the energy conservation equation ...
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The conversion of gaseous atoms K and F to K^(o+) and F^(ɵ) absorbs 0.85 eV of energy. If the IE and Delta_("eg")H^(ɵ) of K and F have magnitudes in the ratio of 7:6 , what is the electron gain enthalpy (Delta_("eg")H^(ɵ)) of fluorine ?

Why do halogens have high electron gain enthalpies (i.e. -Delta_(eg)H^(o.)) ?

Ionisation of energy F^(ɵ) is 320 kJ mol^(-1) . The electronic gain enthalpy of fluorine would be

Give the decreasing order of Delta_(eg)H^(ɵ) of the following elements: F, C, N, O .

Predict from each set, the element which has the more negative electron gain enthalpy (Delta_(eg)H^(ɵ)) . Give reasons: a. C or Si , b. F or Cl , c. O or S

For the gaseous reaction K+F rarrK^(o+)+F^(ɵ) Delta H = 19 kcal mol^(-1) under the condition when cations and anions are prevented by electrostatic separation from combining with each other. The IE_(1) of K is 4.3 eV . Calculate Delta_("eg")H^(ɵ) of F .

Energy is released when an electron is added to neutral isolated gaseous atom in its ground state to give monoanion and this is known as EA , or Delta_(eg)H_(1)^(ɵ) . The greater the amount of energy released the greater is the EA . EA is expressed in eV a"atom"^(-1) or kcal or K\kJ mol^(-1) . The EA values of element depends on the following: i. Nuclear charge ii. Electroniv configuration iii. Atomic size iv. chemical environment

Energy is released when an electron is added to neutral isolated gaseous atom in its ground state to give monoanion and this is known as EA , or Delta_(eg)H_(1)^(ɵ) . The greater the amount of energy released the greater is the EA . EA is expressed in eV a"atom"^(-1) or kcal or K\kJ mol^(-1) . EA values of N and P are exceptionally low, because

Energy is released when an electron is added to neutral isolated gaseous atom in its ground state to give monoanion and this is known as EA , or Delta_(eg)H_(1)^(ɵ) . The greater the amount of energy released the greater is the EA . EA is expressed in eV a"atom"^(-1) or kcal or K\kJ mol^(-1) . Select the correct statements (more than one correct)

Energy is released when an electron is added to neutral isolated gaseous atom in its ground state to give monoanion and this is known as EA , or Delta_(eg)H_(1)^(ɵ) . The greater the amount of energy released the greater is the EA . EA is expressed in eV "atom"^(-1) or kcal or kJ mol^(-1) . Select the correct statement (more than one correct)

CENGAGE CHEMISTRY ENGLISH-PERIODIC CLASSIFICATION OF ELEMENTS AND GENERAL INORGANIC CHEMISTRY-Solved Examples
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  3. The conservation of gaseous atoms K and F to K^(o+) and F^(ɵ) absorbs ...

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  14. Calculate electronegativity of carbon at Pauling scale Given that : ...

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  16. Calculate the electonegativity of silicon using Allred -Rochow method ...

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  17. Calculate the electronegativity value of chlorine on Mulliken's scale,...

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  18. Find the electronegativity of lead with the help of the given valus. S...

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