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Along the period (rarr) atomic//ionic ra...

Along the period `(rarr)` atomic`//`ionic radii and metallic character decreases while `IE`, `EN` , non-metallic character and oxidising power increases. Down the group `(darr)`, atomic`//`ionic radii, metallic character and reducing character increase while `IE` and `EN` decrease. However, `Delta_(eg)H^(ɵ)` becomes less negative down a group but more negative along a period.
Correct order of `IE_(2)` of the following is

A

`F gt O gt N gt C`

B

`O gt N gt F gt C`

C

`O gt F gt N gt C`

D

`C gt N gt O gt F`.

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To determine the correct order of the second ionization energy (IE₂) for the elements carbon (C), nitrogen (N), oxygen (O), and fluorine (F), we need to analyze their electronic configurations and the trends in ionization energy across the periodic table. ### Step-by-Step Solution: 1. **Understand the Electronic Configurations**: - Carbon (C): 1s² 2s² 2p² - Nitrogen (N): 1s² 2s² 2p³ - Oxygen (O): 1s² 2s² 2p⁴ - Fluorine (F): 1s² 2s² 2p⁵ 2. **Identify the First Ionization Energy (IE₁)**: - The first ionization energy is the energy required to remove the outermost electron from a neutral atom. As we move from left to right across a period, the ionization energy generally increases due to increased nuclear charge. 3. **Consider the Second Ionization Energy (IE₂)**: - The second ionization energy is the energy required to remove a second electron after the first has already been removed. The stability of the resulting ion plays a crucial role in determining this value. 4. **Analyze Stability of Ions**: - After the first ionization: - C⁺: 1s² 2s² 2p¹ (relatively stable) - N⁺: 1s² 2s² 2p² (more stable than C⁺) - O⁺: 1s² 2s² 2p³ (half-filled configuration, stable) - F⁺: 1s² 2s² 2p⁴ (less stable than O⁺) - For the second ionization: - C²⁺: 1s² 2s² (stable) - N²⁺: 1s² 2s² 2p¹ (less stable) - O²⁺: 1s² 2s² 2p² (unstable due to removal from half-filled) - F²⁺: 1s² 2s² 2p³ (stable) 5. **Order of IE₂**: - The stability of the resulting ions indicates that the second ionization energy will be highest for oxygen due to its half-filled configuration, which requires more energy to remove an electron. - The order of increasing second ionization energy is: - C < N < F < O ### Final Order of IE₂: The correct order of second ionization energy (IE₂) is: **C < N < F < O**
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Along the period (rarr) atomic // ionic radii and metallic character decreases while IE , EN , non-metallic character and oxidising power increases. Down the group (darr) , atomic // ionic radii, metallic character and reducing character increase while IE and EN decrease. However, Delta_(eg)H^(ɵ) becomes less negative down a group but more negative along a period. Which of the following isoelectronic species has lowest IE_(1) ?

Along the period (rarr) atomic // ionic radii and metallic character decreases while IE , EN , non-metallic character and oxidising power increases. Down the group (darr) , atomic // ionic radii, metallic character and reducing character increase while IE and EN decrease. However, Delta_(eg)H^(ɵ) becomes less negative down a group but more negative along a period. In which of the following pairs, both species have nearly the same size ? (more than one correct)

Along the period (rarr) atomic // ionic radii and metallic character decreases while IE , EN , non-metallic character and oxidising power increases. Down the group (darr) , atomic // ionic radii, metallic character and reducing character increase while IE and EN decrease. However, Delta_(eg)H^(ɵ) becomes less negative down a group but more negative along a period. If the ionic radii of M^(o+) and X^(ɵ) are about 135 p m , then expected values of metallic radii of M and X should be respectively.

Select the correct answer: Non-metallic character down the group - "increases"//"decreases"

Assertion (A) : Metallic character order is K gt Mg gt Al gt B . Reason (R ) : Along the period (rarr) metallic character increases and decreases down the group (darr) .

Assertion :- Metallic character increases on going down the group Reason :- I.E. decreases on going down the group

Fill in the blanks with the appropriate word/s Across a period - Atomic size and metallic character __________ while I.P.. E.A. EN and non-metallic character ____ and nuclear charge _______[ increases/ decreases] Down a group- Atomic size and metallic character _______ while.P, E.A., E.N and non-metallic character _____ and nuclear charge ____________ [increases/decreases]

(a) Electropositive nature of the element(s) increases down the group and decreases across the period (b) Electronegativity of the element decreases down the group and increases across the period (c) Atomic size increase down the group and decreases across a period (left to right) (d) Metallic character increases down the group and decreases across a period On the basis of the above trends of the periodic table, answer the following about the electron with atomic number 3 to 9 (a) Name the most electropositive element among them (b) Name the most electronegative element (c) Name of the element with smallest atomic size (d) Name the element which is a metalloid (e) Name the element which shows maximum valency.

Atomic radii ............................ (increases / decreases) along the period and .............. (increases / decreases) down the group.

Metals have few electrons in their valence shell while non-metals generally have more electrons in their valence shell. Metallic character is closely related to atomic radius and ionisation enthalpy. Metallic character increases from top to bottom in a group and decreases from let to right in a period of periodic table. metallic character is inversely related to electronegativity of element. Q. The electronegativity of the following elements increase in the order:

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