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N(0)//2 atoms of X((g)) are converted in...

`N_(0)//2` atoms of `X_((g))` are converted into `X_((g))^(o+)` by energy `E_(1), N_(0)//2` atoms of `X_((g))` are converted inot `X_((g))^(ɵ)` by energy `E_(2)`. Hence ionisation potential and electron affinity of `X_((g))` per atom are

A

`(2E_(1))/(N_(0)),(2(E_(2)-E_(1)))/(N_(0))`

B

`(2E_(1))/(N_(0)), (2E_(2))/(N_(0))`

C

`((E_(1)-E_(2)))/(N_(0)), (2E_(2))/(N_(0))`

D

None is correct.

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To solve the problem, we need to determine the ionization potential and electron affinity of the element \( X \) based on the given energies \( E_1 \) and \( E_2 \) and the number of atoms \( N_0/2 \). ### Step-by-Step Solution: 1. **Understanding Ionization Potential**: - Ionization potential (IP) is the energy required to remove one mole of electrons from one mole of gaseous atoms. - In the problem, \( N_0/2 \) atoms of \( X \) are converted into \( X^+ \) by energy \( E_1 \). - Therefore, the energy required to ionize \( N_0/2 \) atoms is given as \( E_1 \). 2. **Relating Energy to Ionization Potential**: - The total energy \( E_1 \) for \( N_0/2 \) atoms can be expressed in terms of the ionization potential \( I \): \[ E_1 = \frac{N_0}{2} \times I \] - Rearranging this gives: \[ I = \frac{2E_1}{N_0} \] 3. **Understanding Electron Affinity**: - Electron affinity (EA) is the energy released when one mole of electrons is added to one mole of gaseous atoms. - In the problem, \( N_0/2 \) atoms of \( X \) are converted into \( X^- \) by energy \( E_2 \). - Thus, the energy required to add electrons to \( N_0/2 \) atoms is given as \( E_2 \). 4. **Relating Energy to Electron Affinity**: - The total energy \( E_2 \) for \( N_0/2 \) atoms can be expressed in terms of the electron affinity \( E \): \[ E_2 = \frac{N_0}{2} \times E \] - Rearranging this gives: \[ E = \frac{2E_2}{N_0} \] 5. **Final Expressions**: - Therefore, we have the following expressions for ionization potential and electron affinity: \[ I = \frac{2E_1}{N_0} \] \[ E = \frac{2E_2}{N_0} \] ### Summary of Results: - Ionization Potential \( I = \frac{2E_1}{N_0} \) - Electron Affinity \( E = \frac{2E_2}{N_0} \)

To solve the problem, we need to determine the ionization potential and electron affinity of the element \( X \) based on the given energies \( E_1 \) and \( E_2 \) and the number of atoms \( N_0/2 \). ### Step-by-Step Solution: 1. **Understanding Ionization Potential**: - Ionization potential (IP) is the energy required to remove one mole of electrons from one mole of gaseous atoms. - In the problem, \( N_0/2 \) atoms of \( X \) are converted into \( X^+ \) by energy \( E_1 \). - Therefore, the energy required to ionize \( N_0/2 \) atoms is given as \( E_1 \). ...
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Metals have few electrons in their valence shell while non-metals generally have more electrons in their valence shell. Metallic character is closely related to atomic radius and ionisation enthalpy. Metallic character increases from top to bottom in a group and decreases from let to right in a period of periodic table. metallic character is inversely related to electronegativity of element. Q. 3 N_0//2 atoms of X_((g)) are converted it into X_((g))^(+) by energy E_(1) , 2 N_0//3 atoms of X_((g)) are converted it into X_((g))^(-) by energy E_(2) . hence, ionisation potential and electron affinity of X_((g)) are: ( N_(0) =Avogadro's number)

N_(0)//2 atoms of X(g) are converted into X^(+) (g) by energy E_(1) . N_(0)//2 atoms of X(g) are converted into X^(-) (g) by the energy E_(2) . Hence ionisation potential and electron affinity of X(g) are :

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Calculate the number of oxygen atoms required to ccombine with 7 g of N_(2) to form N_(2)O_(3) when 80% of N_(2) is converted to N_(2)O_(3) .

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The Delta_(eg)H^(ɵ) of Br is 3.4 eV . How much energy in kcal is released when 0.8 g of Br (g) is completely converted to Br^(ɵ) (g) ions. (1 eV = 23.06 kcal mol^(1-)) b. The energy released when 10^(7) atoms of I (g) is converted to I^(ɵ) (g) ions, is 5 xx 10^(-13) J . Calculate Delta_(eg)H^(ɵ) of I (g) in (i) eV "atom"^(-1) and (ii) kJ mol^(-1) .

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CENGAGE CHEMISTRY ENGLISH-PERIODIC CLASSIFICATION OF ELEMENTS AND GENERAL INORGANIC CHEMISTRY-Exercises (Single Correct) Ionisation Energy (Ie)
  1. Which of the elements show least values of ionisation within their per...

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  2. Which of the following has the largest ionisation energy.

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  3. Which one of the following elements has the highest ionisation energy?

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  4. The correct order of second ionisation potentials of carbon, nitrogen,...

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  5. Which has the largest first ionisation energy ?

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  6. Which of the following element has the highest ionisation enregy ?

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  7. Ionisation enthalpy of nitrogen is more than oxygen because of

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  8. The set representing the correct order of the first ionisation potenti...

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  9. The first ionisation potential of which of the element is highest

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  10. Highest ionisation potential in a period is shown by

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  11. The first ionisation energy is maximum for

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  12. Which sequence is correct regarding the first ionisation potential of ...

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  13. The second ionisation potentials in electron volts of oxygen and fluor...

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  14. The value of IE(1), IE(2), IE(3) and IE(4) of an atom are respectively...

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  15. IE(1), IE(2) and IE(3) values are 100, 150 and 1500 eV respectively. T...

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  16. N(0)//2 atoms of X((g)) are converted into X((g))^(o+) by energy E(1),...

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  17. Which of the following ionisation energy valuyes for calcium show a su...

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  18. Which one of the following statements is incorrect in relation to ioni...

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  19. IE(2) for an element is inveriably higher than IE(1) because

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  20. Which of the following metal requires radiation of the lowest waveleng...

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