Home
Class 11
CHEMISTRY
Increasing order of bond angle of (Cl(2)...

Increasing order of bond angle of `(Cl_(2)O, ClO_(2), Cl_(2)O_(7), I_(3)^(ɵ))` is

A

`Cl_(2)O lt ClO_(2) lt Cl_(2)O_(7) lt I_(3)^(ɵ)`

B

`Cl_(2)O lt ClO_(2) lt I_(3)^(ɵ) lt Cl_(2)O_(7)`

C

`I_(3)^(ɵ) lt Cl_(2)O_(7) lt ClO_(2) lt Cl_(2)O`

D

`Cl_(2)O lt Cl_(2)O_(7) lt ClO_(2) lt I_(3)^(ɵ)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the increasing order of bond angles for the compounds \(Cl_2O\), \(ClO_2\), \(Cl_2O_7\), and \(I_3^-\), we will analyze the molecular geometry and the factors affecting the bond angles in each compound. ### Step-by-Step Solution: 1. **Analyze \(Cl_2O\)**: - The molecular geometry of \(Cl_2O\) is bent due to the presence of two lone pairs on the oxygen atom. - According to VSEPR theory, the bond angle is affected by lone pair-lone pair repulsion, which is greater than bond pair-bond pair repulsion. - The approximate bond angle for \(Cl_2O\) is around **110 degrees** due to the steric repulsion between the large chlorine atoms. 2. **Analyze \(ClO_2\)**: - The molecular geometry of \(ClO_2\) is also bent. Chlorine has three lone electrons remaining after forming bonds with two oxygen atoms. - The bond angle is influenced by the presence of lone pairs and bond pairs. The bond angle is approximately **120 degrees** due to the delocalization of the odd electron and bond pair-bond pair repulsions. 3. **Analyze \(Cl_2O_7\)**: - The molecular geometry of \(Cl_2O_7\) is more complex, but it can be approximated to have a bond angle close to **118 degrees**. - Each oxygen atom has two lone pairs, leading to lone pair-lone pair repulsion, which slightly expands the bond angle. 4. **Analyze \(I_3^-\)**: - The molecular geometry of \(I_3^-\) is linear, with three lone pairs on the central iodine atom. - The bond angle in a linear structure is **180 degrees**. ### Conclusion: Now, we can summarize the bond angles: - \(Cl_2O\): 110 degrees - \(ClO_2\): 120 degrees - \(Cl_2O_7\): 118 degrees - \(I_3^-\): 180 degrees ### Increasing Order of Bond Angles: The increasing order of bond angles is: \[ Cl_2O < Cl_2O_7 < ClO_2 < I_3^- \] ### Final Answer: The increasing order of bond angles is: \[ Cl_2O < Cl_2O_7 < ClO_2 < I_3^- \]
Promotional Banner

Topper's Solved these Questions

  • PERIODIC CLASSIFICATION OF ELEMENTS AND GENERAL INORGANIC CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Single Correct) Lattice And Hydration Energy|7 Videos

  • PERIODIC CLASSIFICATION OF ELEMENTS AND GENERAL INORGANIC CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Single Correct)Miscellaneous|10 Videos

  • PERIODIC CLASSIFICATION OF ELEMENTS AND GENERAL INORGANIC CHEMISTRY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises (Single Correct) Acidic, Basicand Amphoteric Character|11 Videos

  • P-BLOCK GROUP 14 - CARBON FAMILY

    CENGAGE CHEMISTRY ENGLISH|Exercise Exercises Archives (Subjective)|9 Videos

  • PURIFICATION OF ORGANIC COMPOUNDS AND QUALITATIVE AND QUANTITATIVE ANALYSIS

    CENGAGE CHEMISTRY ENGLISH|Exercise Assertion Reasoning Type|5 Videos

Similar Questions

Explore conceptually related problems

The bond angle of Cl_(2)O is:

The order of Cl - O bond energy in ClO^(-), ClO_(2)^(-), ClO_(3)^(-), CIO_(4)^(-) is

The correct increasing order of bond dissociation energy for N_2, O_2, F_2, Cl_2 is

The correct order of A-O-A bond angle of (A=H,F or Cl)

The order of acidity of oxides of chlorine . {:(Cl_(2) O ,, Cl_(2) O_(3) ,, Cl_(2) O_(5) ,, Cl_(2)O_(7)), (I ,, II ,, III ,, IV):} is

The correct order of o^(-) bond lengths in ClO^(-), ClO_(2)^(-), ClO_(3)^(-) and ClO_(4)^(-) is

Find out the oxidation number of chlorine in the following compounds and arrange them in increasing order of oxidation number of chlorine. NaClO_(4), NaClO_(3), NaClO, KClO_(2), Cl_(2)O_(7), ClO_(3), Cl_(2)O, NaCl, Cl_(2), ClO_(2) . Which oxidation state is not present in any of the above compounds?

angleFAsF bond angle in AsF_(3)Cl_(2) molecule is :

angleFAsF bond angle in AsF_(3)Cl_(2) molecule is :

Arrange the following in the given order (a) Decreasing ionic size, Mg^(2+),O^(2-),Na^(oplus),F^(ɵ) (b )Increasing first ionisaiton energy : Mg,Al,Si,Na (c ) Increasing bond length F_(2),N_(2),Cl_(2),O_(2) (d) The order of their increasing size: Cl^(ɵ),S^(2-),Ca^(2+),Al^(3+)