Write the Lewis structure for`SO_(5)^(2-)`( Per oxodisulphate ion) .

Explanation

To draw the Lewis structure for the peroxodisulfate ion, \( SO_5^{2-} \), we can follow these steps:

### Step 1: Count the Valence Electrons
- Sulfur (S) has 6 valence electrons.
- Each Oxygen (O) has 6 valence electrons, and there are 5 oxygen atoms, so \( 5 \times 6 = 30 \) valence electrons from oxygen.
- The ion has a \( 2- \) charge, which means we add 2 additional electrons.

**Total valence electrons = 6 (from S) + 30 (from 5 O) + 2 (for the charge) = 38 electrons.**
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