The dipole moment of `HBr` is `2.60 xx 10^(-30)Cm` and the interatomic spacing is `1.41 A` What is the percentage of ionic character of `HBr` ? .

Explanation

To find the percentage of ionic character of HBr, we can follow these steps:

### Step 1: Understand the Given Information
- The dipole moment of HBr (observed dipole moment, \( \mu_{observed} \)) is given as \( 2.60 \times 10^{-30} \, \text{C m} \).
- The interatomic spacing (distance, \( d \)) is given as \( 1.41 \, \text{Å} \), which can be converted to meters:
\[ d = 1.41 \, \text{Å} = 1.41 \times 10^{-10} \, \text{m} \]
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