The bond order in `NO` is 2.5 while that in `NO^(o+)` is 3 Which of the following statement is true for these two species ? .

Options

A. Bond length in `NO gt "in" NO^(o+)`
B. Bond length in `NO^(o+) = "in" NO`
C. Bond length in `NO^(o+) = "in" NO`
D. Bond length in `NO^(o+) gt "in" NO`

Explanation

To determine which statement is true regarding the bond lengths of the species NO and NO^(o+), we will analyze the relationship between bond order and bond length.

### Step-by-Step Solution:

1. **Understanding Bond Order**:
- The bond order is a measure of the number of chemical bonds between a pair of atoms. A higher bond order indicates a stronger bond.

2. **Given Information**:
- The bond order of NO (Nitric Oxide) is 2.5.
- The bond order of NO^(o+) (Nitric Oxide cation) is 3.

3. **Relationship Between Bond Order and Bond Length**:
- There is an inverse relationship between bond order and bond length. This means that as the bond order increases, the bond length decreases.
- Stronger bonds (higher bond order) result in shorter bond lengths due to increased attraction between the bonded atoms.

4. **Comparing Bond Orders**:
- Since the bond order of NO^(o+) (3) is greater than that of NO (2.5), we can conclude that NO^(o+) has a stronger bond.

5. **Conclusion on Bond Lengths**:
- Because NO^(o+) has a higher bond order than NO, it will have a shorter bond length. Therefore, the bond length of NO is greater than that of NO^(o+).

6. **Identifying the Correct Statement**:
- The statement that the bond length of NO is greater than the bond length of NO^(o+) is true.

### Final Answer:
- The bond length of NO is greater than the bond length of NO^(o+).