For `overset(Theta)NH_(2)` the best three-dimensional view is .

Options

A.
B.
C.
D.

Explanation

To determine the best three-dimensional view of the `overset(Theta)NH_(2)` ion (which is the amide ion, `NH2-`), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Atomic Structure**:
- The atomic number of nitrogen (N) is 7. Its electronic configuration is `1s² 2s² 2p³`.
- Since the ion has a negative charge, we add one more electron, making the configuration `2p⁴`.

2. **Determine the Hybridization**:
- In the `NH2-` ion, nitrogen is bonded to two hydrogen atoms. The nitrogen atom has one unpaired electron that will form bonds with the hydrogen atoms.
- The hybridization of nitrogen in this ion is `sp³` because it has four regions of electron density (two bonding pairs with hydrogen and two lone pairs).

3. **Draw the Lewis Structure**:
- The Lewis structure of `NH2-` shows nitrogen in the center with two hydrogen atoms bonded to it and two lone pairs of electrons on nitrogen.
- The structure can be represented as:
```
H
\
N : :
/
H
```

4. **Visualize the 3D Geometry**:
- The `sp³` hybridization leads to a tetrahedral arrangement of electron pairs.
- However, since there are two lone pairs, they will occupy more space and push the bonding pairs closer together.
- The resulting molecular geometry is bent or V-shaped due to the repulsion between the lone pairs.

5. **Select the Best 3D View**:
- The best three-dimensional representation of the `NH2-` ion will depict the nitrogen atom at the center with the two hydrogen atoms forming a bond angle of less than 109.5° (approximately 104.5°) due to the presence of the lone pairs.
- The lone pairs will be positioned in a way that they are as far apart as possible, typically in the equatorial positions of a tetrahedral arrangement.

### Conclusion:
The best three-dimensional view of the `NH2-` ion is a bent structure with nitrogen at the center, two hydrogen atoms bonded to it, and two lone pairs of electrons positioned to minimize repulsion.

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