The `C -C` bond length is `1.54 Å C =C` bond length is `1.33 Å` What is the circumference of benzene ring ? Bond length between single and double bonds `= 1.4 Å` .

Options

A. `(3 xx 1.54 + 3 xx 1.33) Å`
B. `(4 xx 1.54 + 2 xx 1.33) Å`
C. `(6 xx 1.4)Å`
D. `(4 xx 1.33 +2 xx 1.54)Å`

Explanation

To find the circumference of a benzene ring, we can follow these steps:

### Step 1: Understand the structure of benzene
Benzene (C6H6) is a cyclic compound with a hexagonal structure. It consists of 6 carbon atoms connected by alternating single and double bonds. However, due to resonance, all C-C bonds in benzene are of equal length and have characteristics between single and double bonds.

### Step 2: Identify the bond length
From the question, we know:
- The bond length of a C-C single bond is 1.54 Å.
- The bond length of a C=C double bond is 1.33 Å.
- The bond length between a single and double bond (which represents the C-C bond length in benzene) is given as 1.4 Å.

### Step 3: Calculate the circumference of benzene
The circumference of a benzene ring can be calculated using the formula:
\[ \text{Circumference} = \text{Number of bonds} \times \text{Bond length} \]

In benzene, there are 6 C-C bonds. Using the bond length of 1.4 Å:
\[ \text{Circumference} = 6 \times 1.4 \, \text{Å} \]

### Step 4: Perform the calculation
Now, we can calculate the circumference:
\[ \text{Circumference} = 6 \times 1.4 = 8.4 \, \text{Å} \]

### Final Answer
The circumference of the benzene ring is **8.4 Å**.

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