Out of `CH_(3)OH` and `(CH_(3))_(3)N` both exhibit H-bonding .

Explanation

To determine whether the statement "Out of CH₃OH and (CH₃)₃N, both exhibit H-bonding" is correct, we need to analyze the structures of methanol (CH₃OH) and trimethylamine ((CH₃)₃N) and their ability to form hydrogen bonds.

### Step-by-Step Solution:

1. **Understanding Hydrogen Bonding**:
- Hydrogen bonding occurs when a hydrogen atom is covalently bonded to a highly electronegative atom (like nitrogen, oxygen, or fluorine) and is attracted to another electronegative atom in a different molecule.

2. **Analyzing Methanol (CH₃OH)**:
- In methanol, the structure is CH₃-OH. Here, the hydrogen atom is bonded to the oxygen atom, which is highly electronegative.
- This allows methanol to form hydrogen bonds with other methanol molecules. The hydrogen atom of one methanol molecule can interact with the oxygen atom of another methanol molecule, leading to intermolecular hydrogen bonding.

3. **Analyzing Trimethylamine ((CH₃)₃N)**:
- In trimethylamine, the structure is (CH₃)₃N. Here, the nitrogen atom is bonded to three methyl groups (CH₃).
- While nitrogen is electronegative, the hydrogen atoms in trimethylamine are not directly bonded to the nitrogen; instead, they are bonded to carbon atoms, which are not electronegative enough to facilitate hydrogen bonding.
- Therefore, trimethylamine does not exhibit hydrogen bonding in the same way that methanol does.

4. **Conclusion**:
- Since only methanol (CH₃OH) exhibits hydrogen bonding and trimethylamine ((CH₃)₃N) does not, the statement "Out of CH₃OH and (CH₃)₃N, both exhibit H-bonding" is **false**.

### Final Answer:
The statement is false; only methanol (CH₃OH) exhibits hydrogen bonding.