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On hydridisation of one s and one p-orbi...

On hydridisation of one s and one p-orbitals , we get

A

Two mutually perpendicualr orbitals

B

Two orbitals at `180^(@)` .

C

Four obitals directed tetrahedrally

D

Three orbitals in a plane

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B
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According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Correct order of P-P bond length in the following compound is :

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Correct order of P-P bond length in the following compound is :

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Smallest Ohat(S)O bond angle is found in :

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Two elements X and Y combined together to form a covalent compound. If % p-character is found to be 80% in a orbital then the hybridised state of central atom X for the orbital is :

CENGAGE CHEMISTRY ENGLISH-CHEMICAL BONDING AND MOLECULAR STRUCTURE-Archives Single Correct
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  2. Which one among the following does not have the hybrogen bond ?

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  3. On hydridisation of one s and one p-orbitals , we get

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  4. The molecule having one unpaired electrons is .

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  5. The hybridisation of sulphur in sulphur dioxide is

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  6. The bond between two indentical non-metal atoms has a pair of electron...

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  7. Which of the following compounds has a zero dipole momnet ? .

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  8. The species in which the central atom uses sp^(2) hybrid orbitals in i...

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  9. The molecule that has linear structure is

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  10. The Cl-C-Cl angle is 1,1,2,2-tetrachloroethene and tetrachloromethane ...

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  11. The molecule which has pyramidal shape is

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  12. Which of the following is paramagnetic ?

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  13. The molecule which has zero dipole moment is

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  14. The type of hybrid orbitals used by chlorine atom in ClO(2)^(-) is

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  15. The maximum number of H-bonds a water molecule can form are

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  16. Which one of the following molecules is planar?

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  17. The number of types of bonds between two carbon atoms in calcium carbi...

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  18. Among the following species, identify the isostuctural pairs NF(3). ...

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  19. Polar covalent molecules exhibit dipole moment. Dipole moment is equal...

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  20. CN^(Theta) and N(2) are isoelectronic But in contrast to CN^(Theta),N(...

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