The two types of bonds present in `B_(2)H_(6)` are covalent and _____.

Explanation

To determine the two types of bonds present in \( B_2H_6 \) (diborane), we can analyze its structure and bonding characteristics step by step.

### Step-by-Step Solution:

1. **Identify the Molecular Formula**:
- The molecular formula of diborane is \( B_2H_6 \). This indicates that there are two boron (B) atoms and six hydrogen (H) atoms.

2. **Understand the Bonding in Diborane**:
- In diborane, there are two types of hydrogen atoms: terminal hydrogens and bridging hydrogens. The terminal hydrogens are bonded directly to the boron atoms.

3. **Covalent Bonds**:
- The terminal hydrogens form single covalent bonds with the boron atoms. Each terminal hydrogen is connected to a boron atom through a single bond, which involves sharing one pair of electrons (2 electrons total).

4. **Banana Bonds**:
- The bridging hydrogens are involved in what is known as a "banana bond." This bond is a type of three-center, two-electron (3C, 2E) bond. In this bond, two boron atoms and one hydrogen atom share two electrons, creating a bond that is not a typical covalent bond.

5. **Conclusion**:
- Therefore, the two types of bonds present in \( B_2H_6 \) are covalent bonds (for the terminal hydrogens) and banana bonds (for the bridging hydrogens).

### Final Answer:
The two types of bonds present in \( B_2H_6 \) are covalent and **banana bonds**.

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