Fill in the blanks with appropriate choice.
Bond ordr of `N_(2)^(+) is ul(" "P)`while that of `N_(2) is ul(" "Q)`.
Bond order of `O_(2)^(+) is ul(" "R)` while that of `O_(2) is ul(" "S)`.
N - N bond distance `ul(" "T)` when `N_(2)` changes to `N_(2)^(+) ` and when `O_(2)` changes to `O_(2)^(+)` , the O - O bond distance `ul(" "U)`.

Answer

Increases, decrease

Explanation

When `N_(2)` goes to `N_(2)^(o+)` the `N-N` bond distance increases and when `O_(2)` goes to `O_(2)^(o+)` the `O-O` bond distance
The electrons is removed from a bonding molecular orbital in nitrogen and form an antibonding molecular orbital in oxygen .