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The dipole moment of KCI is 3.36 xx 10^(...

The dipole moment of `KCI` is `3.36 xx 10^(-29)Cm` The interatomic distance between `K^(o+)` and `CI^(Θ)` in this unit of `KCI` is `2.3 xx 10^(-10)m` Calculate the percentage ionic character of `KCI` .

Text Solution

Verified by Experts

Assuming `100%` ionic character in `KCI` calculated dipole momnet `=q xx d`
`mu_(cal) = 1.6 xx 10^(-19) xx 2.6 xx 10^(-10)Cm`
` = 4.1 xx 10^(-29)Cm`
Percentage ionic character ` =(mu_(obs))/(mu_(cal))xx100`
`=(3.336 xx 10^(-29) xx 100)/(4.1 xx 10^(-29))`
`=81.36%` .
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