A 5.0 mL solution of `H_(2)O_(2)` liberates 1.27 g of iodine from an acidified KI solution. The percentage strenth of `H_(2)O_(2)` is

Options

A. `11.2`
B. `5.6`
C. `1.7`
D. `3.4`

Answer

D

Explanation

`H_(2)O_(2)-=KI=I_(2)`
`mEq of H_(2)O_(2)=5xxN`
`mEq of I_(2)=W/(EW)xx1000xx1000`
`=1.27/127xx1000=10 mEq`
`[I_(2)=MW=254,EW=(MW)/2=254/2=127]`
`:. mEq of H_(2)O_(2)=mEq of H_(2)O_(2)`
`5xxN=10,:. N=2`
`1N of H_(2)O_(2)=1.7% of H_(2)O_(2)`
`2N of H_(2)O_(2) =3.4 % of H_(2)O_(2)`
Hence the correct option (d)