Hydrogen peroxide in its reaction with `KIO_(4)` and `NH_(4)OH` respectively, is acting as a

Options

A. reducing agent,oxidising agent
B. reducing agent, reducing agent
C. oxidising agent,oxidising agent
D. oxidising agent, reducing agent

Explanation

To determine the role of hydrogen peroxide (H₂O₂) in its reactions with potassium iodate (KIO₄) and ammonium hydroxide (NH₄OH), we will analyze each reaction step by step.

### Step 1: Reaction of H₂O₂ with KIO₄

1. **Write the reaction**:
\[ \text{KIO}_4 + \text{H}_2\text{O}_2 \rightarrow \text{KIO}_3 + \text{H}_2\text{O} + \text{O}_2 \]

2. **Determine oxidation states**:
- For KIO₄:
- K: +1
- O: -2 (4 oxygen atoms contribute -8)
- Let the oxidation state of I be \(x\).
- The equation becomes:
\[ +1 + x + 4(-2) = 0 \implies x = +7 \]
- For KIO₃:
- K: +1
- O: -2 (3 oxygen atoms contribute -6)
- Let the oxidation state of I be \(y\).
- The equation becomes:
\[ +1 + y + 3(-2) = 0 \implies y = +5 \]

3. **Analyze the change in oxidation state**:
- Iodine changes from +7 in KIO₄ to +5 in KIO₃.
- This indicates that iodine is reduced.

4. **Conclusion for this reaction**:
- Since H₂O₂ is causing the reduction of KIO₄, it is acting as a **reducing agent**.

### Step 2: Reaction of H₂O₂ with NH₄OH

1. **Write the reaction**:
\[ \text{NH}_4\text{OH} + \text{H}_2\text{O}_2 \rightarrow \text{N}_2\text{O}_3 + \text{H}_2\text{O} \]

2. **Determine oxidation states**:
- For NH₄OH:
- N: Let the oxidation state be \(x\).
- The equation becomes:
\[ x + 4(-1) + 1 = 0 \implies x = -3 \]
- For N₂O₃:
- Let the oxidation state of N be \(y\).
- The equation becomes:
\[ 2y + 3(-2) = 0 \implies 2y - 6 = 0 \implies y = +3 \]

3. **Analyze the change in oxidation state**:
- Nitrogen changes from -3 in NH₄OH to +3 in N₂O₃.
- This indicates that nitrogen is oxidized.

4. **Conclusion for this reaction**:
- Since H₂O₂ is causing the oxidation of NH₄OH, it is acting as an **oxidizing agent**.

### Final Answer
- In the reaction with KIO₄, H₂O₂ acts as a **reducing agent**.
- In the reaction with NH₄OH, H₂O₂ acts as an **oxidizing agent**.

### Summary
- **H₂O₂ with KIO₄**: Reducing agent
- **H₂O₂ with NH₄OH**: Oxidizing agent