Boron reacts with oxygen at `700^@C` to give `(A)`. Compound `(A)`
reacts with carbon and dry chloride to give `(B)` and carbon
monoxide. `(B)` on reduction with `LiAlH_(4)` gives `( C)` along with
`LiCl` and `AlCl_(3). ( C)` on reaction with ammonia gives `(D)`. Which
on heating gives `(E).(C)` on reaction with `NaH` gives `(F)`.
Compound `(B)` and `(C)` are _____ and _____ respectively.

Options

A. `BCl_(3),B_(2)H_(6)`
B. `BCl_(3),B_(4)H_(10)`
C. `B_(2)Cl_(6),B_(2)H_(6)`
D. `B_2Cl_(3),B_(4)H_(10)`

Explanation

To solve the problem step by step, we will identify each compound based on the reactions described in the question.

### Step 1: Identify Compound (A)
Boron reacts with oxygen at `700°C` to form compound (A). The reaction can be represented as:
\[ 4B + 3O_2 \rightarrow 2B_2O_3 \]
Thus, compound (A) is **Boron trioxide (B2O3)**.

### Step 2: Identify Compound (B)
Compound (A) reacts with carbon and dry chlorine to give compound (B) and carbon monoxide. The reaction can be represented as:
\[ B_2O_3 + 3C + 6Cl_2 \rightarrow 2BCl_3 + 3CO \]
From this reaction, we can see that compound (B) is **Boron trichloride (BCl3)**.

### Step 3: Identify Compound (C)
Compound (B) reacts with lithium aluminum hydride (LiAlH4) to produce compound (C), along with lithium chloride (LiCl) and aluminum chloride (AlCl3). The reaction can be represented as:
\[ 2BCl_3 + 6LiAlH_4 \rightarrow B_2H_6 + 6LiCl + 3AlCl_3 \]
Thus, compound (C) is **Diborane (B2H6)**.

### Step 4: Identify Compound (D)
Compound (C) reacts with ammonia to give compound (D). The reaction can be represented as:
\[ B_2H_6 + 6NH_3 \rightarrow 2BH_2NH_3 + 2BH_4^- \]
This indicates that compound (D) is an ionic species formed during the reaction.

### Step 5: Identify Compound (E)
Compound (D) on heating gives compound (E). The reaction can be represented as:
\[ B_2H_6 + 3NH_3 \rightarrow B_3N_3H_6 + 12H_2 \]
Thus, compound (E) is **Borazine (B3N3H6)**.

### Step 6: Identify Compound (F)
Compound (C) reacts with sodium hydride (NaH) to give compound (F). The reaction can be represented as:
\[ B_2H_6 + NaH \rightarrow NaBH_4 \]
Thus, compound (F) is **Sodium borohydride (NaBH4)**.

### Final Answer
The compounds (B) and (C) are **Boron trichloride (BCl3)** and **Diborane (B2H6)**, respectively.

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