In `B_(2)H_(6)`, there is no `B-B` bond.
The `B_(2)H_(6).2NH_(3)` adduct on heating gives borazine.

Explanation

To solve the question regarding the statements about \( B_2H_6 \) and its adduct with ammonia, we will analyze each statement step by step.

### Step 1: Analyze the Structure of \( B_2H_6 \)

1. **Understanding \( B_2H_6 \)**:
- \( B_2H_6 \) is known as diborane.
- Each boron atom has three valence electrons.

2. **Hybridization**:
- Boron undergoes \( sp^3 \) hybridization.
- In \( B_2H_6 \), there are four normal covalent bonds (two B-H bonds for each boron atom) and two special bonds called "banana bonds" or "three-center two-electron bonds" formed with hydrogen atoms.

3. **Conclusion**:
- There are no direct \( B-B \) bonds in the structure of \( B_2H_6 \) because the boron atoms are connected through hydrogen atoms.

### Step 2: Verify the First Statement

- **First Statement**: "In \( B_2H_6 \), there is no \( B-B \) bond."
- **Verification**: This statement is true as the boron atoms are linked through hydrogen atoms, forming bridging bonds.

### Step 3: Analyze the Reaction of \( B_2H_6 \) with Ammonia

1. **Formation of the Adduct**:
- When \( B_2H_6 \) reacts with ammonia (\( NH_3 \)), it forms an adduct \( B_2H_6 \cdot 2NH_3 \).

2. **Heating the Adduct**:
- Upon heating the adduct, a decomposition reaction occurs.
- The reaction produces borazine (\( B_3N_3H_6 \)) and hydrogen gas (\( H_2 \)).

3. **Structure of Borazine**:
- Borazine is often referred to as inorganic benzene due to its structural similarity to benzene.

### Step 4: Verify the Second Statement

- **Second Statement**: "\( B_2H_6 \cdot 2NH_3 \) adduct on heating gives borazine."
- **Verification**: This statement is also true as the heating of the adduct leads to the formation of borazine.

### Final Conclusion

Both statements provided in the question are correct:
1. There is no \( B-B \) bond in \( B_2H_6 \).
2. The adduct \( B_2H_6 \cdot 2NH_3 \) on heating gives borazine.

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